3 条题解
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1
#include <bits/stdc++.h> using namespace std; int main() { int a[10]; for(int i=1;i<=3;i++) { cin>>a[i]; } sort(a+1,a+3+1); if(a[1]+a[2]<=a[3]) { cout<<"Not triangle"<<endl; } else { if(a[1]*a[1]+a[2]*a[2]>a[3]*a[3]) { cout<<"Acute triangle"<<endl; } if(a[1]*a[1]+a[2]*a[2]==a[3]*a[3]) { cout<<"Right triangle"<<endl; } if(a[1]*a[1]+a[2]*a[2]<a[3]*a[3]) { cout<<"Obtuse triangle"<<endl; } if(a[1]==a[2]||a[2]==a[3]||a[1]==a[3]) { cout<<"Isosceles triangle"<<endl; } if(a[1]==a[2]&&a[2]==a[3]&&a[1]==a[3]) { cout<<"Equilateral triangle"<<endl; } } return 0; } -
1
#include <bits/stdc++.h> using namespace std; int main() { int a[10]; for(int i=1;i<=3;i++) { cin>>a[i]; } sort(a+1,a+3+1); if(a[1]+a[2]<=a[3]) { cout<<"Not triangle"<<endl; } else { if(a[1]*a[1]+a[2]*a[2]>a[3]*a[3]) { cout<<"Acute triangle"<<endl; } if(a[1]*a[1]+a[2]*a[2]==a[3]*a[3]) { cout<<"Right triangle"<<endl; } if(a[1]*a[1]+a[2]*a[2]<a[3]*a[3]) { cout<<"Obtuse triangle"<<endl; } if(a[1]==a[2]||a[2]==a[3]||a[1]==a[3]) { cout<<"Isosceles triangle"<<endl; } if(a[1]==a[2]&&a[2]==a[3]&&a[1]==a[3]) { cout<<"Equilateral triangle"<<endl; } } return 0; }/啥实力啊? Le Zi说话!/
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0
#include <bits/stdc++.h> using namespace std; int main () { int a,s,d,f; cin>>a>>s>>d; if(a>s) { f=a; a=s; s=f; } if(a>d) { f=a; a=d; d=f; } if(s>d) { f=s; s=d; d=f; } if(a+s<=d) { cout<<"Not triangle"<<endl; return 0; } if(aa+ssdd) { cout<<"Right triangle"<<endl; } if(aa+ss>dd) { cout<<"Acute triangle"<<endl; } if(aa+ss<d*d) { cout<<"Obtuse triangle"<<endl; } if(as || ad || sd) { cout<<"Isosceles triangle"<<endl; } if(as && sd) { cout<<"Equilateral triangle"<<endl; } return 0; }
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信息
- 编号
- 2311
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 3
- 标签
- 递交数
- 164
- 已通过
- 40
- 上传者