1 条题解

  • 3
    @ 2025-4-4 18:23:17

    原始人方法

    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	char a;
    	cin>>a;
    	if(a=='a')
    	{
    		cout<<"A";
    	}
    	if(a=='b')
    	{
    		cout<<"B";
    	}
    	if(a=='c')
    	{
    		cout<<"C";
    	}
    	if(a=='d')
    	{
    		cout<<"D";
    	}
    	if(a=='e')
    	{
    		cout<<"E";
    	}
    	if(a=='f')
    	{
    		cout<<"F";
    	}
    	if(a=='g')
    	{
    		cout<<"G";
    	}
    	if(a=='h')
    	{
    		cout<<"H";
    	}
    	if(a=='i')
    	{
    		cout<<"I";
    	}
    	if(a=='j')
    	{
    		cout<<"J";
    	}
    	if(a=='k')
    	{
    		cout<<"K";
    	}
    	if(a=='l')
    	{
    		cout<<"L";
    	}
    	if(a=='m')
    	{
    		cout<<"M";
    	}
    	if(a=='n')
    	{
    		cout<<"N";
    	}
    	if(a=='o')
    	{
    		cout<<"O";
    	}
    	if(a=='p')
    	{
    		cout<<"P";
    	}
    	if(a=='q')
    	{
    		cout<<"Q";
    	}
    	if(a=='r')
    	{
    		cout<<"R";
    	}
    	if(a=='s')
    	{
    		cout<<"S";
    	}
    	if(a=='t')
    	{
    		cout<<"T";
    	}
    	if(a=='u')
    	{
    		cout<<"U";
    	}
    	if(a=='v')
    	{
    		cout<<"V";
    	}
    	if(a=='w')
    	{
    		cout<<"W";
    	}
    	if(a=='x')
    	{
    		cout<<"X";
    	}
    	if(a=='y')
    	{
    		cout<<"Y";
    	}
    	if(a=='z')
    	{
    		cout<<"Z";
    	}
    	if(a=='A')
    	{
    		cout<<"a";
    	}
    	if(a=='B')
    	{
    		cout<<"b";
    	}
    	if(a=='C')
    	{
    		cout<<"c";
    	}
    	if(a=='D')
    	{
    		cout<<"d";
    	}
    	if(a=='E')
    	{
    		cout<<"e";
    	}
    	if(a=='F')
    	{
    		cout<<"f";
    	}
    	if(a=='G')
    	{
    		cout<<"g";
    	}
    	if(a=='H')
    	{
    		cout<<"h";
    	}
    	if(a=='I')
    	{
    		cout<<"i";
    	}
    	if(a=='J')
    	{
    		cout<<"j";
    	}
    	if(a=='K')
    	{
    		cout<<"k";
    	}
    	if(a=='L')
    	{
    		cout<<"l";
    	}
    	if(a=='M')
    	{
    		cout<<"m";
    	}
    	if(a=='N')
    	{
    		cout<<"n";
    	}
    	if(a=='O')
    	{
    		cout<<"o";
    	}
    	if(a=='P')
    	{
    		cout<<"p";
    	}
    	if(a=='Q')
    	{
    		cout<<"q";
    	}
    	if(a=='R')
    	{
    		cout<<"r";
    	}
    	if(a=='S')
    	{
    		cout<<"s";
    	}
    	if(a=='T')
    	{
    		cout<<"t";
    	}
    	if(a=='U')
    	{
    		cout<<"u";
    	}
    	if(a=='V')
    	{
    		cout<<"v";
    	}
    	if(a=='W')
    	{
    		cout<<"w";
    	}
    	if(a=='X')
    	{
    		cout<<"x";
    	}
    	if(a=='Y')
    	{
    		cout<<"y";
    	}
    	if(a=='Z')
    	{
    		cout<<"z";
    	}
    	return 0;
    }
    

    多是多了点,麻烦是麻烦点,但是一定是满分,

    • 1

    信息

    编号
    2288
    时间
    1000ms
    内存
    256MiB
    难度
    2
    标签
    递交数
    105
    已通过
    69
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